Chemistry, asked by zanikakel, 1 month ago

RNH4Cl -> RNH2 + H2Cl is this correct?

Answers

Answered by barani7953
2

Explanation:

GIVEN :-

Two force P and Q .

Maximum resultant = 300.

Minimum resultant = 800 N.

TO FIND :-

The value of P and Q.

SOLUTION :-

The maximum resultant force can be written as,

\begin{gathered} \implies \sf \: P + Q = 300....(1) \\ \end{gathered}

⟹P+Q=300....(1)

The minimum resultant force can be written as,

\begin{gathered}\implies \sf \: P - Q = 800....(2) \\ \end{gathered}

⟹P−Q=800....(2)

From equation 1 we have,

\begin{gathered}\implies \sf \: P = 300 - Q ....(3) \\ \end{gathered}

⟹P=300−Q....(3)

From equation 2 we have,

\begin{gathered}\implies \sf \: P = 800 + Q ....(4) \\ \end{gathered}

⟹P=800+Q....(4)

On comparing equation 3 and 4 we get,

\begin{gathered}\implies \sf \: 300 - Q = 800 + Q \\ \end{gathered}

⟹300−Q=800+Q

\begin{gathered}\implies \sf \: - 2Q = 500 \\ \end{gathered}

⟹−2Q=500

\begin{gathered}\implies \sf \: - Q = \dfrac{500}{2} \\ \end{gathered}

⟹−Q=

2

500

\begin{gathered}\implies \sf \: Q = - 250 \\ \end{gathered}

⟹Q=−250

Now substitute the value of Q in equation 1,

\begin{gathered}\implies \sf \: P - 250 = 300 \\ \end{gathered}

⟹P−250=300

\begin{gathered}\implies \sf \: P= 300 + 250 \\ \end{gathered}

⟹P=300+250

\implies \sf \: P=550⟹P=550

Hence the value of P is 550 and value of Q is -250.

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