Question

RNSIT - MBA
m 37. Between hours 2 PM and 4 PM, the average number of phone calls per minute w as
into the switch board of a company is 2.35. Find the probability that dums
particular minute, there will be at-least 2 phone calls.​

Answer 1

Answer:

P( X <=  2 )  0.5438131170

Step-by-step explanation:

Poisson probability distribution is used when we want to calculate probability distribution of the number of events occurring in a given time period provided average occurrence is given in data.

Solution

Formula for Poisson probability distribution

Probability(P)(X for given lamda) = e^(-lamda)*lamda^X / X!

As per given question statement, lamda is 2.5, e is equal to 2.71828

P( X <=  2 ) = P(0) + P(1) + P(2)

Putting values in formula;

P(0:2.5) = 0.082084999

P(1:2.5) = 0.205212497

P(2:2.5) = 0.256515621

P( X <=  2 ) = 0.082084999 + 0.205212497 + 0.256515621

P( X <=  2 )  0.5438131170