Question

road, if the diameter of the cylindrical wheel of the road roller is 98 cm and length is 1.25 m.
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Answer 1

Answer:

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Step-by-step explanation:

In 1 revolution, area of road covered = 2πrh

=2×

7

22

×63×2.5=990 m

2

Therefore,

Area covered in 900 revolutions = 900×990=891000 m

2

Answer 2

Answer:

346932sq.cm

Step-by-step explanation:

diameter of wheel =98cm

radius of wheel=49cm

length of wheel=125cm

circumference of wheel=2π r (r+h)

2×2217×49(48+125)

=385.48sq.cm

so, in 1 round of roller complete 38548sq.cm

so, total area covered in 900rounds=900×38548

=346932sq.cm

but approx 34.69 sq. cm

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