road roller in form of cylinder has a diameter of 0.7 M and its width is 1.2 M Find the least number of revolution that the road roller make in order to level a playground of size 120 M and 44
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Answer:
area of playground =120*44 m^2
in cylinder,
height =1.2 m
diameter =0.7 m
radius= 0.35
c. s. a =2πrh
=2*22/7*0.35*1.2
=2.64
no of revolution =area of playground/c.s.a
=120*44/2.64
=2000
Step-by-step explanation:
brofist0072:
Thanks
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