Question

Robert perchased two cars of equal price.He paid repairing charges of Rs.2000 for each car.He then sold the two cars for a total of Rs.420000 making a 20% profit on one car and incurring a 10% loss on the other.Find---
(i) the cost price of each car.
(ii) the percentage of profit on the whole transaction.​

Answer 1

Answer:

Step-by-step explanation:

Let C.P of both cars be Rs x each.

Total C.P of each after payment = x + 2000

S.P = (100 + profit or 100 - loss) / 100 * C.P

so, S.P of 1st car = (100 + 20) / 100 * (x + 2000) = (12x + 24000) / 10

and S.P of 2nd car = (100 - 10) / 100 * (x + 2000) = (9x + 18000) / 10

Total S.P = 420000

so (12x + 24000) / 10 + (9x + 18000) / 10 = 420000

or (21x + 42000) / 10 = 420000

or (21x + 42000) = 4200000

or 21x = 4200000 - 42000

or x = 4158000/21 = 198000

so, C.P of each car = 198000