ROBERTS FATHER IS FOUR TIMES AS OLD IS NOW ROBERT. AFTER 5 YEARS HIS FATHER WILL BE THREE TIMES OF HIS AGE. WHAT IS THE AGE OF BOTH?
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let age of his father=x
and his is =y
then
A.T.Q
x=4y
so, x-4y=0 ..........(1)
and then after 5years
his father age is=x+5
and his age is =3(y+5)
so, x+5=3y+15
x-3y=10 ...............(2)
using elimination method in equation (1) and (2)
so, x-4y=0
x-3y=10
- +. -
----------------------
-y= -10
y= 10
put value of y=10 in equation (1)
x-4(10)=0
x-40 = 0
x = 40
so the age of his father is 40 and Robert age is 10.
and his is =y
then
A.T.Q
x=4y
so, x-4y=0 ..........(1)
and then after 5years
his father age is=x+5
and his age is =3(y+5)
so, x+5=3y+15
x-3y=10 ...............(2)
using elimination method in equation (1) and (2)
so, x-4y=0
x-3y=10
- +. -
----------------------
-y= -10
y= 10
put value of y=10 in equation (1)
x-4(10)=0
x-40 = 0
x = 40
so the age of his father is 40 and Robert age is 10.
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