Question

Robin, the cook, can cut either 120 carrots or 72 potatoes or 60 beetroots in t mins. One day, during the first K mins, he spent an equal amount of time cutting each of three types of vegetables. However, in the next K mins, he cut exactly n carrots, n beetroots and n potatoes. If he cut a total of 282 vegetables during the first 2K mins on that day, what is value of n​

Answer 1

Answer:

$the \: value \: of \: n = the \: number \\ \: of \: vegetable \\ \: robin \: cuts \:$

Answer 2

The value of n is 45.

GIVEN: The cook can cut either 120 carrots or 72 potatoes or 60 beetroots in t mins.
TO FIND: Value of n​
SOLUTION:

As we are given,
Robin can cut either 120 carrots or 72 potatoes or 60 beetroots in t mins.

Therefore,

Efficiency ratio of Robin=

Carrot: Potatoes: Beetroots = 120:72:60

Carrot: Potatoes: Beetroots =10:6:5

The number of cut vegetables in 1st part of k must be greater than 2k

So, the total ratio must be greater than 282/2=141

Which number of cut vegetables must be smaller than 141 and divisible

by 3.

So, a total of 1st k=10+6+5=21…. Multiplying by 7,8,9,10...

6 isn't acceptable as smaller than 141.

S0,21*7=147.

Remaining 282-147=135

Dividing by 3, 135/3=45.

n=45

Therefore, the required value of n is 45.

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