Question

Robin went to market to purchase bats and balls. The cost of one bats is ₹500 and cost of one balls is ₹50. If he spent ₹1750 of 8 items, how many bats and balls he purchase

Answer 1

Answer:

I can tell you this answer by typing but by frist you have to add the bat and ball and the number obtained number should be subtracted by 1750 and then multiple by 8 and then divide by 50 and the number have to been in decimal form

Answer 2

Step-by-step explanation:

Given:

Robin went to market to purchase bats and balls. The cost of one bats is ₹500 and cost of one balls is ₹50. If he spent ₹1750 of 8 items.

To find:How many bats and balls he purchased?

Solution:

Let x number of balls and y number of bats are purchased.

ATQ

Total 8 items were purchased.

Thus,

$\bold{x + y = 8} \: \: ...eq1$

Cost of one bat is 500 Rs,so cost of y bats =500y Rs

Cost of one ball is 50 Rs,so cost of x balls =50x Rs

So,

$\bold{50x + 500y = 1750} \: \: ...eq2$

Now,solve these two equation

Multiply eq1 by 50 and subtract eq2-eq1

$50x + 500y = 1750 \\ 50x + 50y = 400 \: \: \: \: \\ ( - ) \: \: \: \: \: \: ( - ) \: \: \: \: \:\: ( - ) \\ - - - - - - - - \\ 450y = 1350 \\ \\ y = \frac{1350}{450} \\ \\ \boxed{\bold{y = 3}}$

put the value of y in eq1

$x + y = 8 \\ \\ x + 3 = 8 \\ \\ x = 8 - 3 \\ \\ \boxed{\bold{x = 5}}$

Final answer:

No. of balls purchased: 5

No. of bats purchased: 3

Verification:

= 5×50+3×500

= 250+1500

= 1750 Rs

Hope it helps you.

To learn more on Brainly:

solve the following system of linear equation graphically: 3x+y-11=0 and x-y-1=0

shade the region bounded by these lines...

https://brainly.in/question/3050092