Question

robot was 4 times as old as his son 8 years ago. after 8 years,rohit will be twice as old as his son. what are their present ages?with fill soluction

Answer 1

let's assume that rohit's present age is x and his son's 
present age is y. 2 equations formed using these.
x-8 = 4(y-8) -> represtning 8 ago from present time.
x+8 = 2(y+8) -> representing 8 yrs ahead from now.
subtract 2nd equation from 1st. the resulting equation w'd 
be: 2y-48=-16
y=16
x=2y+8
=40
hence Rhit's present age is 40, his son's present age is 16 
yrs.

Answer 2

Answer:

Step-by-step explanation:

Given :-

Robit was 4 times as old as his son 8 years ago.

After 8 years, rohit will be twice as old as his son.

To Find :-

Their present ages

Solution :-

Let son's age 8 years ago be x years.

Rohit's age 8 years ago be 4x years.

Son's age after 8 years = (x + 8) + 8 = (x + 16) years.  

Rohit's age after 8 years = (4x + 8) + 8 = (4x+ 16) years.  

⇒ 2 (x + 16) = 4x + 16  

⇒ 2x = 16  

⇒ x = 16/2

⇒ x = 8.

Hence, son's 'present age = (x + 8) = 16 years.  

Rohit's present age = (4x + 8) = 40 years.