Question

Roger has a nail that is 12 centimeters long. He measures and records the length of the nail as 15 centimeters. What is the percent error in Roger's measurement?

A. 15%
B. 17%
C. 20%
D. 25%

Answer 1

Roger has a nail that is 12 centimeters long. He measures and records the length of the nail as 15 centimeters.

We have to determine the percent error in his measurement.

Error percentage = $\frac{measured value - accepted value}{accepted} \times 100$

Roger's measured value was 15cm but his accepted value was 12cm.

= $\frac{15-12}{12} \times 100$

= $\frac{3}{12} \times 100$

= $\frac{100}{4}$

= 25%

So, There is 25% of error in Roger's measurement.

Option D is the correct answer.

Answer 2

Answer:

Option D is correct=25%

I have this on my test.

hope it helps all you really have to do is multiply the numbers given and use fractions