Question

Roger pushes a box on a 30° incline. If he applies a force of 60 newtons parallel to the incline and displaces the box 10 meters along the incline, how much work will he do on the box?

Answer 1

workdone= force  x   displacement

the box is being moved  in staight i.e inclinedso

force = 60 cos30

60 is number of newtons, 30 is angle

force =  51.96 ..... N

WORKDONE  = 51.96  X   `10

                          = 519.6

                              = 520 joules

  hope   this may help u .