Roha has to travel from his school to his house which is at a distance of 10 km. He covers the first half of the distance at a speed of 30 km/h, the next 2 km at a speed of 15 km/h and the remaining distance at a speed of 45 km/h. What is Rohit's overage speed during the whole journey?
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Answer:
Let the total distance travelled be x km Then total time taken =
10
x/3
+
20
x/3
+
60
x/3
=
30
x
+
60
x
+
180
x
=
180
6x+3x+x
=
180
10x
=
18
x
hrs Then average speed = =
Totaltimetaken
Totaldistancetravelled
=
x/18
x
km/hr = 18 km/hr
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