Math, asked by irene04, 20 hours ago

Rohan, a student of class IX book a ola cab for travelling the tourist places of Jaipur city. The taxi fare
in a city is as follows. Fare for the first km is ₹8 and for the subsequent distance it is ₹5 per km.
Answer the following questions:
i) Consider the distance covered as x km and the total fare as ₹ y, write a linear equation for this information.

a) 5x + y + 3 = 0 b) 5x - y - 3 = 0
c) 5x - y + 3 = 0 d) 9x + y + 3 = 0
ii) Compare the above equation with ax + by + c = 0, and find the value of (a + b + c).
a) 6 b) 7 c) 8 d) 9

iii) If total fare is ₹93, then find the total distance.

a) 16 km b) 17 km c) 18 km d) 19 km.

iv) If the distance covered is 11km, then find total fare.

a) ₹58 b) ₹68 c) ₹48 d) ₹88

v) If fare for first kilometre is ₹12 and fare have subsequent distance is ₹8 per km then write a linear
equation for the information.

a) 4x + y + 4 = 0 b) 6x - y + 6 = 0
c) 8x - y + 4 = 0 d) 7x - y + 7 = 0

Answers

Answered by shakuntlasihag67
27

Answer:

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Step-by-step explanation:

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Answered by amitnrw
6

Given :  The taxi fare in a city is as follows. Fare for the first km is ₹8 and for the subsequent distance it is ₹5 per km.

distance covered as x km and the total fare as ₹ y

To Find :   write a linear equation  

Compare the above equation with ax + by + c = 0  and find the value of (a + b + c).

If total fare is ₹93, then find the total distance.

If the distance covered is 11km, then find total fare.

If fare for first kilometre is ₹12 and fare have subsequent distance is ₹8 per km then write a linear equation for the information.

Solution:

Fare for the first km is ₹8 and for the subsequent distance it is ₹5 per km.

=> y = 8 + 5(x - 1)

=> y = 8 + 5x -5

=> 5x - y +  3 = 0

Correct option is c) 5x - y + 3 = 0

ax + by + c = 0

a = 5 , b = -1  c = 3

a + b + c =  5 - 1 + 3  = 7

Correct option is b) 7

total fare is ₹93,

=> 5x - 93 + 3 = 0

=> x = 18

Correct option is c) 18 km

distance covered is 11 km

5(11) - y + 3 = 0

=> y = 58

Correct option is  a) ₹58

first kilometre is ₹12 and fare have subsequent distance is ₹8

y = 12 + 8(x - 1)

=> y = 8x + 4

=> 8x - y + 4 = 0

Correct option is  c) 8x - y + 4 = 0

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