Question

. Rohan bought a rhombus shaped field , whose diagonals are 2400 m and 1000 m. Rohan wants to fence it but don't know the length of its boundary. (a) Which of the following is the length of side of field ?

1 point

1200 m

1300 m

1400 m

1600 m

(b) What will be the cost of fencing the length of boundary of the field,if cost of fencing is 70 rupees per meter ?

1 point

364000

336000

150000

none of the above

(c) What is the area of land Rohan bought ?

1 point

6,00,000 square m

9,00,000 square m

12,00,000 square m

4,00,000 square m

​

Answer 1

Answer:

1) 1600

2)364000

3)400000sq m

Step-by-step explanation:

Answer 2

Answer:

a) let ABCD be the sides and point O at which the diagonals meet

AO = 500 m

OC = 500 m

(Diagonals bisect each other)

BO = 1200 m

OD = 1200 m

(Diagonals bisect each other)

Each forms a right triangle inside so we can use Pythogorean theorm

a² + b² = c²

500² + 1200² = c²

=>2500 + 14400 = c²

=>16900 = c²

=> c = √16900

=> c = 130

b) perimeter = 4s

1 side = 130 m

Per meter = 70 rs

Perimeter = 130 x 4

                 = 520 m

Cost = 520 x 70

        = 36400 rs

c) Area of rhombus = pq

/2

p = 2400 q = 1000

2400x1000/2 = 2400000/2

= 1200000 m²

Hope its helpful :D