Math, asked by soumyabehera217, 9 hours ago

Rohan bought a rhombus shaped field,whose diagonals are 2400 m and 1000 m.Rohan wants to fence it but don’t know the length of its boundary.-Which of the following is the length of side of field?
A ) 1200 metres
B ) 1300 metres
C ) 1400 metres
D ) 1500 metres


Rohan bought a rhombus shaped field,whose diagonals are 2400 m and 1000 m.Rohan wants to fence it but don’t know the length of its boundary. What will be the cost of fencing the length of boundary of the field,If cost of fencing is 70 rupees per metre ?
A ) 3,36,000 Rupees
B ) 3,56,000 Rupees
C ) 3,64,000 Rupees
D ) 1,05,000 Rupees


What is the area of land Rohan bought ?
A) 12,00,000m^2
B ) 6,00,000 m^2
C ) 9,00,000 m^2
D ) 3,00,000 m^2


D and E are respectively the midpoints on the sides AB and AC of a triangle ABC and BC = 6 cm. If DE || BC, then the length of DE (in cm) is
(A) 2.5
(B) 3
(C) 5
(D) 6


The lengths of the diagonals of a rhombus are 16 cm and 12cm. Then, thelength of the side of the rhombus is
(A) 9 cm
(B) 10 cm
(C) 8 cm
(D) 20 cm


A flag pole 18 m high casts a shadow 9.6 m long. Find the distance of the top of the pole from the far end of the shadow.
(A) 25.6
(B) 20.4
(C) 23.7
(D) 32.5​

Answers

Answered by ishtakhatri63
2

Answer:

a) let ABCD be the sides and point O at which the diagonals meet

AO = 500 m

OC = 500 m

(Diagonals bisect each other)

BO = 1200 m

OD = 1200 m

(Diagonals bisect each other)

Each forms a right triangle inside so we can use Pythogorean theorm

a² + b² = c²

500² + 1200² = c²

=>2500 + 14400 = c²

=>16900 = c²

=> c = √16900

=> c = 130

b) perimeter = 4s

1 side = 130 m

Per meter = 70 rs

Perimeter = 130 x 4

                = 520 m

Cost = 520 x 70

       = 36400 rs

c) Area of rhombus = pq

/2

p = 2400 q = 1000

2400x1000/2 = 2400000/2

= 1200000 m²

Hope its helpful :D

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