Question

Rohan buys 12 computers and 12 printers if the cost of one computer and one printer is 56233 and 7867 respectively find the total cost incurred by rohan. Use distributive property

Answer 1

the cost of 1 computer is 56233
the cost of such 12 computer=12×56233
=674796
the cost of 1 printer is 7867
the cost of such 12 printers=12×7867
=94404
total cost incurred by Rohan=674796+94404
=769200

Answer 2

Answer: Rs 7,69,200

Step-by-step explanation:

Rohan buys 12 computers at the cost of 56,233 and 12 printers at the cost of 7,867.

Total cost incurred by Rohan

12×56,233+12×7,867

=12×(56,233+7,867)

=12×(64100)

=12×64100

=7,69,200