Question

Rohan buys 12 computers and 12 printers. If the cost of one computer and one
printer is 56,233 and 37,867 respectively, find the total cost incurred by Rohan.
(Use distributive property of multiplication.)​
please give me answer as fast you can

Answer 1

Step-by-step explanation:

cost of one computer =56233

cost of one printer =37867

Rohan bought 12 computers and 12 printers

cost of 12 computers=56233(12)=674796

cost of 12 printers =37867(12)=454404

Total cost incurred by Rohan=674796+454404

=1129200

Answer 2

Step-by-step explanation:

$number \: of \: computer \: rohan \: bought \: = 12 \\ cost \: of \: one \: computer \: = 56233 \\ number \: of \: printers \: rohan \: bought \: = 12 \\ cost \: of \: one \: printer \: = 37867 \\ total \: cost \: = 12(56233 + 37867) = 1129200$