Rohan buys 12 computers and 12 printers. If the cost of one computer and one
printer is 56,233 and 7,867 respectively, find the total cost incurred by Rohan.
(Use distributive property of multiplication.)
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Answers
Answered by
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Answer: This should be easy.....
Cost of 1 computer=56233Rs.
Cost of 2 cmputers=7867Rs.
∴Cost of 12 computers= cost of 1 computer×12
=56233×12=674769Rs.
Similarly, the cost of 12 printers=7867×12
=94404Rs.
HOPE IT HELPS YOU!
Answered by
0
Answer:
Total computers = 12
Total printers = 12
One computer = 56,233
Twelve computers = 12 x 56,233
= 6,74,796
One printer = 7,867
Twelve printers = 12 x 7,867
= 94,404
Total cost = 6,74,796 + 94,404
= 7,69,200
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