Question

Rohan buys 12 computers and 12 printers. If the cost of one computer and one
printer is 56,233 and 7,867 respectively, find the total cost incurred by Rohan.
(Use distributive property of multiplication.)
13​

Answer 1

The cost of one computer is 56,233

so the cost of 12 computers =

12×56,233=674796

the cost of one printer is 7,867

so the cost of 12 printers=

12×7,867=94404

total cost incurred by rohan =

674796+94404=769200

Please give me some thanks

Answer 2

Answer:

total no. of computer=12

cost of 1 computer=56233

total no. of printers=12

cost of 1 printer=7867

✓ by using distributive property a(b+c)

✓ 12(56233+7867)

✓ 674,796+94,404= 769,200rupees

Step-by-step explanation:

therefore,769200 is the total money incurred by Rohan

hope it helps you