Question

Rohan had a bag of balls. 1/6 of them were green balls, 1/4 of them were red balls, 15 of them were black balls. The remaining 48 were yellow balls. How many balls were there in the bag?
Please provide an explanation for the answer.

Answer 1

Let Rohan has x number of ball
                     Green ball=x/6
                     Redballs =x/4
                     Black balls =15
                     Yellow balls =48
ATQ                  x6/+x/4+15+48=x
                     ⇒    x-x/6-x/4= 63
                     ⇒   (12x-2x-3x)/12=63
                      ⇒   7x=63*12
                       ⇒    x=108

Answer 2

Let the number of ball in the bag be x .

Then A.T.Q
Green balls=x/6    
Red balls =x/4
Black balls = 15
Yellow balls = 48

Now ,

x + x   + 15 + 48 = x
6    4

4x + 6x  + 63 = x
   24 

10x - x = - 63
 24

10x - 24x = - 63
     24

- 14x = - 1512

x = 108

Hence the number of balls in the bag = 108.

Green balls = x/6      = 108/6      = 18

Red balls = x/4         = 108/4      = 27