Question

Rohan had...... How many candies does he have left

Answer 1

Step-by-step explanation:

9x^2y-15^y^2-17x^2y-8y^2

=-8x^2y-23y^2

Option C is correct

Answer 2

Candies left with Rohan =

$= > \bf {9x}^{2}y - {15y}^{2} - ( {17x}^{2} y + {8y}^{2} ) \\ = > \sf {9x}^{2} y - {15y}^{2} - {17x}^{2} y - {8y}^{2} \\ = > \bf (9 - 17) {x}^{2} y - (15 + 8) {y}^{2} \\ = > \boxed{ \tt \red{ - 8 {x}^{2} y - 23 {y}^{2} }}$

• Option (c) is correct answer.