Question

rohan has ₹680 in ₹10 notes and ₹5 coins. if the number of ₹5 coins is twice the number of ₹10 notes. find the total number of each denomination rohan has.​

Answer 1

$\large\underline{\sf{Solution-}}$

Let assume that

Number of notes of ₹ 10 denominations = x

Number of notes of ₹ 5 denominations = 2x

So,

Total amount in ₹ 5 denominations = 5 × 2x = 10x

Total amount in ₹ 10 denominations = 10 × x = 10x

According to statement,

Total amount = 680

$\rm \implies\:10x + 10x = 680$

$\rm \implies\:20x = 680$

$\rm \implies\:x =34$

So, it means,

Number of notes of ₹ 10 denominations = 34

Number of notes of ₹ 5 denominations = 68

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Basic Concept Used :-

Writing System of Linear Equation from Word Problem.

1. Understand the problem.

• Understand all the words used in stating the problem.

• Understand what you are asked to find.

2. Translate the problem to an equation.

• Assign a variable (or variables) to represent the unknown.

• Clearly state what the variable represents.

3. Carry out the plan and solve the problem.

Answer 2

Answer:

Number 0f ₹10 Notes = 34

Number 0f ₹5 Coins = 68

Step-by-step explanation:

Total money with Rohan = ₹680

Let the number of ₹10 notes be x

The number or ₹5 coins is 2x (Twice the ₹10 notes)

So, total money with Rohan of ₹10 denomination = 10x

Total money with Rohan of ₹5 denomination = 5 X (2x) = 10x

So,

10x + 10x = 680

=> 20x = 680

=> x = 680/20

=> x = 34

Hence, number of ₹10 notes = x = 34

Hence, number of ₹5 coins = 2x = 2 X 34 = 68

                                 Reviewing the Answer

So, total money with Rohan of ₹10 denomination = 10x = 10 X 34 = 340

Total money with Rohan of ₹5 denomination = 5 X (2x) = 10x = 10 X 34 = 340

So, ₹340 + ₹340 = ₹680 which is the total money with Rohan.

Hope it Helps Many!!

Have a nice day!