Question

Rohan has five coins which he tossed simultaneously 250 times and record the outcomes as given below: Outcomes 5 tails 4 tails 3 tails 2 tails 1 tail 0 tails Frequency 45 25 50 35 65 30
if he wants to toss these 5 coins again, answer
1 probability of getting 3 tails is
2 probability of getting 2 tails is
3 probability of getting least 4 tails is
4 probability of getting almost 1 tail is
5 probability of getting no head is ​

Please answer my question correctly and please explain I will mark him brainliest

Answer 1

Answer:

Step-by-step explanation:

1)   1/5

2)7/50

3) 7/25

4) 23/50

5)  4/5

Answer 2

Answer:

(1) P [getting 3 tails] = 1/5

(2) P [getting 2 tails] = 7/50

(3) P [getting atleast 4 tails] = 7/25

(4) P [ getting atmost 1 tail] = 19/50

(5) P [getting no head] = P [5 tails] = 9/50

Step-by-step explanation:

number of tails:  5    4      3      2       1      0

Frequency:       45  25    50    35    65    30

probability of an event = number of favorable occurances of an event/ total number of occurances

total number of outcomes = 250

(1) P [getting 3 tails] = $\frac{50}{250}$ = $\frac{1}{5}$ = 1/5

(2) P [getting 2 tails] = $\frac{35}{250}$ = $\frac{7}{50}$ = 7/50

(3) P [getting atleast 4 tails] = $\frac{45+25}{250}$ = $\frac{70}{250}$ = $\frac{7}{25}$ = 7/25

(4) P [atmost 1 tail] = $\frac{65+30}{250}$ = $\frac{95}{250}$ = $\frac{19}{50}$ = 19/50

(5) P [getting no head] = P [5 tails] =  $\frac{45}{250}$ = $\frac{9}{50}$ = 9/50