Rohan has three resistors, each of resistance 4 Ω. Draw a diagram and show
the working of how he would join these three resistors to get an equivalent
resistance of 6 Ω.
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Explanation:
Correct option is B)
To get an equivalent resistance of 6 ohms, we have to use both parallel and series connection in the circuit. First, the two resistors are connected in parallel to obtain a combined resistance of 2 ohms and then the combined resistance in connected in series with the third resistor to give a total resistance of 6 ohms.
That is, for the two resistors in parallel the resistance is given as
4
1
+
4
1
=
0.5
1
=2ohms and this is added with the resistance of the third resistor in series as 2+4=6 ohms.
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