Rohan has three resistors, each of resistance 4 Ω. Draw a diagram and show
the working of how he would join these three resistors to get an equivalent
resistance of 6 Ω
Answers
Answer:this buj
Explanation:
Resistance of each resistor R=9Ω
Two resistor connected across A and B are connected in parallel.
Equivalent resistance across A and B R
AB
=
R+R
R×R
=
2
R
=
2
9
=4.5Ω
This equivalent resistance is connected in series to another resistor R.
So equivalent resistance across A and C R
AC
=R
AB
+R=4.5+9=13.5Ω
Answer:
Explanation:
1. equivalent resistance = 13.5 Ω Join two resistors in parallel and one in series as shown in 1st figure We know, in parallel,
1/R=1/R₁+1/R₂
Here, R₁ = R₂ = R3 = 90
Now, 1/R' = 1/90 + 1/90
R' = 9/20 = 4.5
Ω So, equivalent resistance, Req = R¹ + R3
[R' and R3 in series]
Req = 4.50 +90 = 13.50
2. Equivalent resistance = 60 two resistors are in series which is parallel with 3rd resistor as shown in 2nd figure.
now, R' = R₁ + R₂ = 9 + 9 = 180 [ R₁ and
R₂ are in series] now, equivalent resistance, Req = R'R3/(R'
+ R3) [R' and R3 are in parallel ]
.. Req = 18 × 9/(18 + 9) = 18 x 9/27 = 60
