Rohan has three resistors, each of resistance 4 omp draw and show the working of how he would join these three resistors to get an equivalent resistance of 6 omp
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Answer
To obtain a combined resistance of 9 ohms, three resistors each of resistance 6 ohm should be connected in a parallel circuit and one in series.
In a parallel circuit, the equivalent resistance of all the resistors connected is equal to the reciprocal value of the sum of the individual resistances.
In a series circuit, the equivalent resistance of all the resistors connected is equal to the sum of the resistance values of each of the individual resistor.
So in a parallel circuit, total resistance =
or
R t =
In a series circuit, total resistance = R1 +R2 + R3
(i) To get 9 ohms, two resistors should be connected in parallel and one in series.
So,
Rt in parallel will be
= 3 ohms
One resistor is connected in series with the 3 ohms, so
Rt in series will be Rt = R1 +R2 = 6+3 = 9 ohms
(ii) To obtain a combined resistance of 4 ohms, two resistors (of 6 ohms each) are connected in series and one in parallel to the series.
So,
Rt in series = R1 +R2 = 6+6 = 12 ohms