Question

Rohan has two rods of lenghts 198 cm and 360 cm. He wants to cut the two rods into shorter pieces of the same lenght with no left overs. what is the greatest possible lenght of cach of the shorter pieces

Answer 1

Answer:

18 cm rods

Step-by-step explanation:

we need to find the HCF of 198 & 360

198 = 2 × 3 × 3 × 11

360 = 2 × 2 × 2 × 3 × 3 × 5

HCF is 2 × 3 × 3 = 18

the rods should be cut in length of 18 cm

198 = 18 × 11

360 = 18 × 20

we get a total of 31 pieces of equal length of 18cm.