Question

Rohan is 2 years elder than rohit. Five years ago one third of his age was equal to three-sevenths of rohit's age. calculate their present age

Answer 1

Answer:

Let Rohit's age be x years.

Since, Ritu is 5 years younger than her brother Rohit, her age =x−5

Given, father is 25 years older than Ritu => Father's age =x−5+25=x+20

Four years ago, Rohit's age =x−4, Ritu's age =x−9, Father's age =x+16

Given, four years ago, the fathers age was twice the sum of the ages of Rohit and Ritu

=>x+16=2(x−4+x−9)

=>x+16=4x−26

=>3x=42

x=14

Hence, Rohit's age =14 years

Ritu's age =x−5=9 years

Father's age =x+20=34  years

Answer 2

Answer:

Present ages of Rohan = 14 years , Rohit = 12 years .

Step-by-step explanation:

Given :-

• Rohan is 2 years elder than Rohit .
• 5 years ago 1/3 of Rohan's age = 3/7 of Rohit's age .

To find :- Present age of Rohan and Rohit .

Solution :-

Step 1) Let the age of Rohan be ' x ' , and Rohit be ' y ' .

given , Rohan is 2 years elder than Rohit  , x = 2 + y ---- (1)

Step 2) 5 years ago , $\frac{1}{3}*x = \frac{3}{7}*y$ --- (2)

therefore , $7x = 9y$ -- (3)

At present , Rohan's age = x + 5 , Rohit's age = y + 5 ---- (4)

solving equation (1) and (3) , we get

$7x = 9y \\7(2+y) = 9y \\14 + 7y = 9y \\14 = 2y \\y = 7$

hence , $x = 2+y \\x = 9$

Present age ,

Rohan = x + 5 = 9 + 5 = 14 years

Rohit  = y + 5 = 7+5 = 12 years .

Answer :-

Present ages of Rohan = 14 years , Rohit = 12 years .

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