Question

Rohan is a cashier in a bank . He has currency notes of denomination .100, .50 and .10

respectively. The ratio of the number of these notes is 2:3:5. The total cash with Rohan is

4,00,000. How many notes of each denomination does she have?​

Answer 1

The ratio of the notes is =  2 : 3 : 5

2 x number of Rs 100 notes  

3 x number of Rs 50 notes

5 x  number of Rs 10 notes

Then the total value of the currency notes will be =

  2 x  × ₹ 100 + 3 x × ₹ 50 + 5 x × ₹ 10  =  ₹ 4, 00, 000

=>    200 x + 150 x + 50 x = ₹ 4, 00, 000

=>    400 x = ₹ 4, 00, 000

  =>  x = 1, 000

   Hence,

There are :

2 x = 2,000 notes of ₹ 100  

3 x = 3,000 notes of ₹ 50

5 x = 5, 000 notes of ₹ 10

hope it helps !!

Answer 2

Answer:

Let, Rohan had each denominations be 2x, 3x, 5x

therefore, 2x+3x+5x=400000

=10x=400000

x=400000/10

x=40000

now, 100 rupee notes = 2×40000

=80000

number of notes =80000/100

=800.

amount of 50 rupees notes = 3×40000

=120000

number of notes = 120000/50

=2,400.

and, amount of 10 rupees notes = 5×40000

=200000

number of notes =200000/10

=20000.