Math, asked by udhayanudhaya, 23 days ago

Rohan is wrapping a rectangular box that measures 5x6x12
(inches). How many square feet of wrapping paper does he
required?
A: 529sq.inches
B: 229sq.inches
C: 324sq.inches
D: 579sq.inches​

Answers

Answered by SavageBlast
76

Given:-

  • Rohan is wrapping a rectangular box that measures 5 × 6 × 12 (inches).

To Find:-

  • Paper does he required

Formula Used:-

  • {\boxed{\bf{TSA\:of\: Cuboid=2(lb + bh + hl)}}}

Solution:-

Firstly,

\bf :\implies\:TSA\:of\: Cuboid=2(lb + bh + hl)

Here,

  • l = 5 inches

  • b = 6 inches

  • h = 12 inches

Putting Values,

\sf :\implies\:TSA\:of\: Cuboid=2(lb + bh + hl)

\sf :\implies\:TSA\:of\: box=2(5\times6 + 6\times12 + 12\times5)

\sf :\implies\:TSA\:of\: box=2(30 +72+ 60)

\sf :\implies\:TSA\:of\: box=2\times162

\bf :\implies\:TSA\:of\: box=324\:inches^2

Hence, 324 inches sq feet of paper is required to wrap the rectangular box.

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More Formulas for Cuboid:-

  • \bf Lateral\:Surface\:Area=2h(l + b)

  • \bf Volume=l\times b\times h

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