rohan's mother gave him Rs 3xy2 and his father gave him Rs5(xy2+2).out of this total money he spent.Rs (10-3xy2)on his birthday party. how much money is left with him?
Answers
Answer:
Given :-
Rohan's mother gave him Rs. 3xy²
His father gave him Rs.5(xy²+2).
The money he spent Rs. (10-3xy²) on his birthday party.
To find :-
The money is left with him.
Solution :-
Given that
The money is given to Rohan by his mother = Rs. 3xy²
The money is given to Rohan by his father = Rs. 5(xy²+2)
= (5×xy²)+(5×2)
= Rs. (5xy²+10)
Total money is given to Rohan
= 3xy² +5xy²+10
= Rs. (8xy²+10)
Money he spent on his birthday party
= Rs. (10-3xy²)
Remaining money = Total given money - spent money
=> (8xy²+10)-(10-3xy²)
=> 8xy²+10-10+3xy²
=> (8xy²+3xy²)+(10-10)
=> (8+3)xy²+0
=> 11xy²
Therefore , Remaining money = Rs.11xy²
Answer :-
The money is left with Rohan is Rs.11xy²
Given :-
- Rohan's mother gave him Rs. 3xy²
- Rohan's father gave him Rs. 5(xy² + 2)
- Rohan spent Rs. (10 - 3xy²)
To Find :-
Money left with him
Solution :-
Total money Rohan have = Money given by mother + Money guven by father
⇒ 3xy² + 5(xy² + 2)
⇒ 3xy² + 5xy² + 10
⇒ 8xy² + 10
Now,
Money left = Total money - Money spent
⇒ Money left = 8xy² + 10 - (10 - 3xy²)
⇒ Money left = 8xy² + 10 - 10 + 3xy²
⇒ Money left = 11xy²