Question

Rohan's mother gave him Rs 3xy2 his father gave him Rd 5 xy2 + 2 out of this money he spent Rs 10- 3xy2 on his birthday party how much money left with ​

Answer 1

Answer:

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Explanation:

Given:

Amount given by mother = 3xy^{2}3xy

2

Amount given by father = 5xy^{2} +25xy

2

+2

Amount spent by Rohan = Rs. \: 10-3xy^{2}Rs.10−3xy

2

To Find:

Amount left with Rohan.

Solution:

According to the question,

Total money Rohan got = 3xy^{2} +5xy^{2} +103xy

2

+5xy

2

+10

\implies 8xy^{2} +10⟹8xy

2

+10

Now,

Money spent by Rohan = 10-3xy^{2}10−3xy

2

Therefore,

Money left with Rohan = 8xy^{2} +10 -(10-3xy^{2} )8xy

2

+10−(10−3xy

2

)

\begin{gathered}\implies 8xy^{2} +10-10+3xy^{2}\\:\implies \boxed{Rs. \: 11xy^{2} }\end{gathered}

⟹8xy

2

+10−10+3xy

2

:⟹

Rs.11xy

2

Thus, Rs. 11xy² is left with Rohan.