(Rohan sells a T.V. to Roshan for 8800 making a profit of 10%|| Roshan sell the T. V. to
Sushant making a profit of 10%. Find the amount paid by Rohan and Roshan respectively to
buy the T.V. Find the purchase price of Sushant
Answers
Answer:
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Step-by-step explanation:
Amount paid by Rohan to buy the T.V is Rs 8000.
Amount paid by Roshan to buy the T.V is Rs 8800.
Purchased price of Sushant is Rs.9680.
Step-by-step explanation:
To find:-
Amount paid by Rohan to buy the T.V.
Amount paid by Roshan to buy the T.V .
Purchase price of Sushant.
Solution:-
For Rohan :
Selling price = Rs.8800
Profit percent = 10%
Profit = 8800 - C.P
Profit is 8800 - C.P
Now,
\sf \longrightarrow 10 = \dfrac{8800 - C.P}{C.P} \times 100 ⟶10=
C.P
8800−C.P
×100
\sf \longrightarrow 10 \times C.P = (8800 - C.P ) \times 100⟶10×C.P=(8800−C.P)×100
\sf \longrightarrow \dfrac{10}{100} \times C.P = 8800-C.P⟶
100
10
×C.P=8800−C.P
\sf \longrightarrow \dfrac{C.P}{10} = 8800 - C.P⟶
10
C.P
=8800−C.P
\sf \longrightarrow C.P = 10 \times (8800-C.P)⟶C.P=10×(8800−C.P)
\sf \longrightarrow C.P = 88000 - 10\: C.P⟶C.P=88000−10C.P
\sf \longrightarrow 10 \: C.P + C.P = 88000 ⟶10C.P+C.P=88000
\sf \longrightarrow 11 \: C.P = 88000 ⟶11C.P=88000
\sf \longrightarrow C.P = \dfrac{88000}{11} ⟶C.P=
11
88000
\longrightarrow \blue{\boxed{\sf \bold{C.P=8000}}\star} ⟶
C.P=8000
⋆
Cost price of T.V for Rohan is Rs 8000.
Cost price of T.V will be the amount which Rohan is paying to buy T.V .
Thus, Rohan paid Rs.8000 to buy T.V.
For Roshan :
Selling price of T.V for Rohan = Cost price for T.V of Roshan
[Because Rohan is Selling T.V to Roshan]
Cost price of T.V for Roshan is Rs 8800 .
Cost price of T.V is the price which he will pay to Rohan to buy T.V .
So, Roshan paid Rs.8800 to Rohan to buy T.V.
Roshan is getting profit 10% by selling T.V to Sushant.
We need to find, in how many rupees he sells T.V to Sushant.
So,
Profit = S.P - 8800
Profit is S.P - 8800.
Now,
\sf \longrightarrow \dfrac{S.P - 8800}{8800} \times = 10 ⟶
8800
S.P−8800
×=10
\sf \longrightarrow (S.P - 8800) \times 100 = 10 \times 8800 ⟶(S.P−8800)×100=10×8800
\sf \longrightarrow (S.P - 8800) \times 100 = 88000 ⟶(S.P−8800)×100=88000
\sf \longrightarrow S.P - 8800 = \dfrac{88000}{100} ⟶S.P−8800=
100
88000
\sf \longrightarrow S.P - 8800 = 880 ⟶S.P−8800=880
\sf \longrightarrow S.P = 880 + 8800⟶S.P=880+8800
\longrightarrow \pink{\boxed{\sf \bold{S.P = 9680}}\star} ⟶
S.P=9680
⋆
Selling price of Roshan is Rs. 9680.
For Sushant :
Selling price of Roshan = Cost price of T.V for Sushant.
Cost price of T.V for Sushant is Rs.9680.
Cost price will be the amount which sushant pay to buy T.V.
Thus,
Sushant purchased T.V for Rs 9680.
______________________________
We have used Profit and Profit percent formulas here. Formulas are :
• \boxed{\sf \bold{Profit = S.P - C.P}}
Profit=S.P−C.P
• \boxed{\sf \bold{Profit \: percent = \dfrac{Profit}{C.P} \times 100}}
Profitpercent=
C.P
Profit
×100
Here, C.P and S.P are Cost price and Selling price respectively.
Similarly, In above answer S.P and C.P are Selling price and Cost price.