Rohan started his journey from equator to Northern Hemisphere. He reached at 23.5 °North .Name Rohan's destination(reaching point). *
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Let the length of total journey be X km. According to the given condition,
2/5 × x + 1/3 xX + 1/6 × X + 3 = X. X 2X/5 + X/3 + X/6 +3 = X L.C.M. of 5, 3 and 6 is 30. Multiply both side by 30.
12X + 10X + 5X +90 = 30 X
27X +90 30X
Transpose 27X to Right
90 30X27X
90 = 3X
Transposing 3 to left.
90/3 = X
30 = X
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