Question

Rohan Started works In 1995 at an annual salary of rs 5000
and received an increment of rs 200 each year . in which year did his income reach rs 7000?

Answer 1

the ap will be 5000,5200,5400............7000
a=5000,d=200,an=l=7000
an=a+(n-1)d
7000=5000+(n-1)200
7000-5000=(n-1)200
2000=(n-1)200
2000÷200=n-1
10=n-1
n=10+1
n=11
in 11th yr Rohan income will be 7000.
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Answer 2

the annual salary drawn by rohan in the years 1995,1996,1997,.. etc is Rs 5000,Rs5200,Rs5400..... ,Rs7000.



the list of these nos. is 5000,5200,5400,......, 7000


It forms an Ap.

$\\ [ a_{2} - a_{1} = a_{3} - a{2}=200$

$a_{n} = 7000$

7000 = a + (n - 1) (d)


7000 = 5000 + (n - 1) (200)


200(n - 1) = 7000 - 5000


n - 1 = 2000/200 = 10


n = 10+1 = 11


so in the 11 th year ( in 2005) of this service Rohan drew an annual salary of Rs 7000


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