Math, asked by rajuk645117, 5 hours ago

Rohit and madhur shared a sum money in the ratio 3:2. After Rohit gave 1/2 of his share to Madhur, madhur had Rs 140. what was the sum of money they together had?​

Answers

Answered by srijana984
0

Answer:

3:2=1:6

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Answered by vinpnm
0

Answer:

Since we have given that

Ratio of sum of money of Rohit and Madhur is 3:2

So, Let the sum of money Rohit has be 3x

Let the sum of money Madhur has be 2x

Now, we have given that

\text{ Rohit gave }\frac{1}{2}\text{ of his share to Madhur} Rohit gave

2

1

of his share to Madhur

According to question,

\begin{gathered}2x+\frac{3x}{2}=140\\\\\frac{4x+3x}{2}=140\\\\\frac{7x}{2}=140\\\\x=140\times \frac{2}{7}\\\\x=40\end{gathered}

2x+

2

3x

=140

2

4x+3x

=140

2

7x

=140

x=140×

7

2

x=40

So, Amount Madhur has

2x=2\times 40=802x=2×40=80

And

Amount Rohit has

4x=4\times 40=1604x=4×40=160

Total amount of money they together had

160+80=240160+80=240

Hence, They together had Rs.240

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