Math, asked by mdazfaralmtupam8425, 1 year ago

Rohit and madhur shared a sum of money in the ratio 3:2 . After Rohit gave 1/2 of his share to madhur, madhur had rs 140. what was the sum of money they together had?

Answers

Answered by RenatoMattice
32

Answer: They together had Rs.240

Explanation:

Since we have given that

Ratio of sum of money of Rohit and Madhur is 3:2

So, Let the sum of money Rohit has be 3x

Let the sum of money Madhur has be 2x

Now, we have given that

\text{ Rohit gave }\frac{1}{2}\text{ of his share to Madhur}

According to question,

2x+\frac{3x}{2}=140\\\\\frac{4x+3x}{2}=140\\\\\frac{7x}{2}=140\\\\x=140\times \frac{2}{7}\\\\x=40

So, Amount Madhur has

2x=2\times 40=80

And

Amount Rohit has

4x=4\times 40=160

Total amount of money they together had

160+80=240

Hence, They together had Rs.240

Answered by sonakshisuman430
7

Answer:

They together had 240 rupees

Step-by-step explanation:

Ratio of sum of money of Rohit and madhur is 3:2

So,

Let the sum of money Rohit has be 3x

Let the sum of money madhur has be 2x

Now,

We have given that

Rohit gave 1/2 of his share to madhur

According to question,

2x+3x/2=140

4x+3x/2=140

7x/2=140*2/7

x=40

So,

Amount madhur has

2x=2*40=80

Amount Rohit has

4x=4*40=160

Total amount of money they together had

160+80=240

Hence,

They together had 240 rupees

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