Question

Rohit and Mohit borrowed Rupees 6000 each at the rate of 12% per annum for a period of 2 years and 3 years respectively find the difference in the interest paid by them

Answer 1

iRohit S.I(simple interested) = PxTxR/100 = 6000x12x2=14000
Mohit S.I (simple interested)=PxTxR/100=6000x12x3=21000

Difference =21000-14000=7000

I hope you get it

Answer 2

Answer:

720

Step-by-step explanation:

Rohit S.I (simple interest) = PXRXT/100

= 6000X12X2/100

= 1440

Mohit S.I (simple interest) = PXRXT/100

= 6000X12X3/100

= 2160

subtract = 2160-1440

= 720

Rohit and Mohit difference between

= 720