rohit and Rahul went to see the tower in the city They amazed with the height of tower as it was a high they were looking at the top of tower from two different places. If the angles of elevation of the top of a tower from two points distant a and b .(a>b) from its foot and in the same straight line from it are respectively 30 and 60 then find the height of the tower
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height of the tower = √3 (a - b) /2 if angle of elevation from a & b are 30 & 60 deg
Step-by-step explanation:
Tan 60 = h/b
=> √3 = h/b
=> b = h/√3
Tan 30 = h/a
=> 1/√3 = h/a
=> a = h√3
a - b = h√3 - h/√3
=> a - b = h ( √3 - 1/√3)
=> a - b = h ( 3 - 1) /√3
=> a - b = h 2 /√3
=> h = √3 (a - b) /2
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