Math, asked by pantnandini360, 6 hours ago

Rohit borrowed Rs. 24,000 at 7.5percent per year. How much money will he pay at the end of 4th years to clear his debt?
please answer correctly

Answers

Answered by PopularStar
36

Principal (P) = Rs. 24,000

Rate (R) = 7.5% P.A.

Time (T) = 4 Years

Solution:

S.I. = \dfrac{P×R×T}{100}

S. I= ₹ \dfrac{24,000×7.5×4}{100}

S. I= ₹ 240 × 7.5×4

S. I= 240 × 30

S. I= Rs. 7200

Amount needed to clear the debt at the end of 4th year.

= Rs. 24000 + Rs. 7200 = Rs. 31200

Answered by lostsprit32
0

Answer:

Principal (P) = Rs. 24,000

Rate (R) = 7.5% P.A.

Time (T) = 4 Years

Solution:

S.I. = P×R×T 100

100

P×R×T

S. I= ₹ 24,000×7.5×4 100

100

24,000×7.5×4

S. I= ₹ 240 × 7.5×4

S. I= 240 × 30

S. I= Rs. 7200

Amount needed to clear the debt at the end of 4th year.

= Rs. 24000 + Rs. 7200 = Rs. 31200

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