Rohit borrowed rs 60000 from a bank at 9% per annum for 2 years. he lent this sum of money to rohan at 10% per annum for 2 years. how much did rohit earn from this transaction?
Answers
Answered by
58
Answer:
Principal amount lent out by Rohit (P) = Rs. 60000
Time period (T) = 2 years
Rate of interest (R) = 10% p.a.
Interest = (P×R×T100)
= (60000×10×2100)
= Rs. 12000
Principal amount borrowed by Rohit from the bank (P) = Rs. 60000
Time period (T) = 2 years
Rate of interest (R) = 9% p.a.
Interest = (P×R×T100)
= (60000×9×2100)
= Rs. 10800
Amount gained by Rohit = Rs. 12000 – 10800 = Rs. 1200
Answered by
10
Answer:
Time periods=2yrsRate of intrest=10%p.a.
Intrest=p×r×t÷100
60000×9×2÷100=12000
Explanation:
time period=2yrs
rate%=9%
intrest=p×r×t÷100
60000×9×2100
=10800
amount gained by Rohit=12000-10800=1200
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