Question

rohit bought two scooters for rs 18000each by selling one at a profit of 25% and the other at a loss of 20% he neither gains or loss find the selling price of each scooter​

Answer 1

Let the C.P. of the 1

st

scooter = Rs. x.

Then, C.P. of the 2

nd

scooter = Rs. (18000−x)

S.P. of 1

st

scooter = Rs. x×

100

125

​

= Rs.

4

5x

​

S.P. of 2

nd

scooter = Rs. (18000−x)×

100

80

​

= Rs.

5

4

​

(18000−x)

Since Mohan neither gains nor loses, his total S.P. = Total C.P.

⇒

4

5x

​

+

5

4

​

(18000−x)=18000

⇒

4

5x

​

−

5

4x

​

=18000−14400=3600

⇒

20

25x−16x

​

=3600⇒9x=3600×20

⇒x=

9

3600×20

​

=8000

∴ C.P. of 1

st

scooter = Rs. 8000

C.P. of 2

nd

scooter = Rs. 10,000.