Question

Rohit buys chocolate and burger in the ratio 5:3 for Re 20 and is 60 respectively he earned a profit of 10% on chocolates and 20% on burgers if it's total sale is Rs 48900 find the number of chocolate and burgers

Answer 1

Answer:

Number of chocolates = 750

Number of burgers = 450

Step-by-step explanation:

Let the common ratio be x

Then, the number of chocolates = 5x

Number of burger = 3x

Total cost of chocolates = 5x × 20 = 100x

Total cost of burgers = 3x × 60 = 180x

Profit on chocolates = 10%

Therefore, the selling price of chocolates = 100x × 1.1 = 110x

Profit on burgers = 20%

Selling price of burgers = 180x × 1.2 = 216x

Total selling cost = 110x + 216x = 326x

According to the question

$326x = 48900$

$\implies x=\frac{48900}{326}$

$\implies x=150$

Therefore number of chocolates $=5\times 150=750$

Number of burgers $=3\times 150=450$

Hope this helps.