Question

Rohit descends into a mine shaft at the rate 5 m / min. If the descend starts from
15 m above the ground level, how long will it take to reach the shaft 60 m below
the ground level?

Answer 1

Answer: Hi bro here is your answer

Step-by-step explanation:

Starting position of mine shaft is = 10m above ground

but,

it moves in opposite direction so it travels the distance (-350 m ) below the ground.

Total distance covered by mine shaft = 10m - (-350m)

= 10 + 350

= 360m

Now, taken to cover a distance of 6m by it = 1 minute

Time taken to cover a distance of 1m by it = 16 min⁡\frac{1}{6\ }\min6 1​min

Therefore, tie taken to a cover a distance of 360m = 16× 360 = 60 min⁡  \frac{1}{6}\times\ 360\ =\ 60\ \min\ \ 61​× 360 = 60 min  

60 minutes = 1 hour

thus, in one hour the mine shraft reaches = 350 below the ground.

Answer 2

Answer:

I don't know please tell me