rohit donated 1/5 of his monthly income to an non-government organisation (ngo) working for education of girl child,spent 1/4 of his salary on food ,1/3 on the rent and 1/15 on other expenses .he is left with rs 9000
Answers
x = x/5+x/4+x/3+x/25+9000, where
x/5 = Amount given to NGO
x/4 = Amount spent on food
x/3 = amount spent on rent
x/15 = amount spent on other expenses
9000 = balance.
The LCM of 5, 4, 3 and 15 is 60. Thus, we get
x = (12x+15x+20x+4x+540000) / 60
60x = 51x + 540000
or 60x-51x = 540000
9x = 540000
Therefore, x = 540000 / 9 = 60,000
Thus, Rohit's salary is Rs. 60,000.
Answer:
Let \: Rohit \: monthly \: salary = Rs \:xLetRohitmonthlysalary=Rsx
\begin{gathered}Donation \: to \: non-government\\ organisation = \frac{x}{5}\end{gathered}
Donationtonon−government
organisation=
5
x
Amount\:spent \:for \: Food = \frac{x}{4}AmountspentforFood=
4
x
Rent = \frac{x}{3}Rent=
3
x
Other \: expenses = \frac{x}{15}Otherexpenses=
15
x
Salary \:left = Rs \:9000Salaryleft=Rs9000
/* According to the problem given */
Monthly \: salary - Expenses = 9000Monthlysalary−Expenses=9000
x - \Big( \frac{x}{5}+\frac{x}{4}+\frac{x}{3}+\frac{x}{15}\Big) = 9000x−(
5
x
+
4
x
+
3
x
+
15
x
)=9000
\implies x - \Big( \frac{12x+15x+20x+4x}{60}\Big) = 9000⟹x−(
60
12x+15x+20x+4x
)=9000
\implies x - \frac{51x}{60} = 9000⟹x−
60
51x
=9000
\implies \frac{60x-51x}{60} = 9000⟹
60
60x−51x
=9000
\implies \frac{9x}{60} = 9000⟹
60
9x
=9000
\implies x = 9000 \times \frac{60}{9}⟹x=9000×
9
60
\implies x = 60000⟹x=60000
Therefore.,
\red {Rohit \: monthly \: salary} \green{= Rs\:60000 }Rohitmonthlysalary=Rs60000
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