Rohit focused the image of a candle flame on a white screen using a convex lens. He noted down the position of the candle , screen and lens as under : Position of candle = 26.0 cm Position of convex lens = 50.0 cm Position of screen = 74.0 cm
i) What is the focal length of the convex lens?
ii) Where will the image be formed if he shifts the candle towards the lens at a position of 38 cm?
iii) Draw a ray diagram to show the formation of the image in case (ii) as said above?
Anu726:
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Answers
Answered by
1
u = 50 - 26 = 24 cm
v = 74 - 50 = 24 cm
2f = 24 cm
f = 24/2 = 12 cm
ii) u = 50 - 38 = 12 cm
i.e. Candle is at f
So, image is formed at infinity.
I hope my answer is wright..
v = 74 - 50 = 24 cm
2f = 24 cm
f = 24/2 = 12 cm
ii) u = 50 - 38 = 12 cm
i.e. Candle is at f
So, image is formed at infinity.
I hope my answer is wright..
Answered by
2
Let the optic centre be the terminal point of 50 cm
U = 50 - 26 = 24 cm
V = 74 - 50 = 24 cm
Since U (object distance) = V ( image distance) The object must be placed at 2F.
So 2F = 24cm
F= 24/2 = 12 cm
Therefore focal length is 12 cm.
Now candle is shifted to 38 cm
Therefore U = 50 - 38 = 12 cm
Since the Object is placed at the focus the image will be formed at infinity.
Hope it helps!!
Cheers!!
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