Rohit hit 4 times century in 10 innings.so find the probability that he did not hit a century.
Answers
Answer:
total no of outcomes= 10 did not hit a bounadary=10‐4=6 p(not hitting boundary)= 6/10=0.6
Therefore the probability that Rohit did not hit a century is '0.6'.
Given:
Total number of innings played by Rohit = 10
Number of centuries hit by Rohit = 4
To Find:
The probability that he did not hit a century.
Solution:
The given question can be solved very easily as shown below.
Given that,
Total number of innings played by Rohit = 10
Number of centuries hit by Rohit = 4
Probability of Rohit hits a century = P(A) = ( Number of centuries hit by Rohit ) / ( Total number of innings played )
⇒ Probability of Rohit hits a century = P(A) = 4/10 = 0.4
The probability that Rohit does not hit a century = P(A)¹ = 1 - P(A)
⇒ The probability that Rohit does not hit a century = P(A)¹ = 1 - 0.4 = 0.6
Therefore the probability that Rohit did not hit a century is '0.6'.
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