Math, asked by Tusharyadav07, 9 months ago

Rohit is twice as old as fahim after 12 years their combined ages will be seven times fahims present age what are their present ages

Answers

Answered by prettykohli
3

Answer:

Step-by-step explanation:

Answer:

rohit's age=12

fahim's age=6

Step-by-step explanation:

Let rohit's and fahim's present ages be x and y respectively.

since, rohit is twice old as fahim.

so, x=2y

and, after 12 years ,

rohit's age =x+12

and, fahim's age =y+12

according to question,

x+12+y+12=7(y)

x+y+24=7y

3y+24=7y

4y = 24

y=6

and x=2y=2×6=12

Answered by Nicu48
1

Answer:

Rohit's age=12

Fahim's age=6

Step-by-step explanation:

Let Rohit's and Fahim's present ages be x and y respectively.

Since, Rohit is twice old as Fahim.

So, x=2y

And, after 12 years Rohit's age will be =x+12, and, Fahim's age will be=y+12

According to question,

=x+12+y+12=7(y)

=x+y+24=7y

=3y+24=7y

=4y = 24

=y=6 and x=2y=2*6=12

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