Math, asked by zaidip46, 6 months ago

Rohit lent out Rs.14700 on simple interest and the same sum on compound interest for 2 years at 162 %per annum. Find the difference of the interests received by Rohit after 2 years

Answers

Answered by Anonymous
0

Rohit borrowed =62,500, T=2yrs, R=10%

S.D=  

100

p+r

​  

=  

100

62,500×2×10

​  

 

⇒12,500

Rohit lent =62,500, T=2yrs, R=10%.(Compounded)

Amount =62,500(1+  

100

10

​  

)  

2

 [∵A=P(1+  

100

1

​  

)  

n

]

=62,500(1.1)  

2

 

=75625

C.D=75625−62500=13125

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