Math, asked by rahulkumar6272733, 1 year ago

Rohit obtained 45 mark out of 80 what percent mark did he get

Answers

Answered by gaurav2013c
122
Maximum marks = 80

Marks obtained = 45

Percentage = 45 × 100 / 80

= 45 × 10 / 8

= 45×5/4

= 225/4

= 56.25%
Answered by mysticd
33

Answer:

 Percentage \: of \: marks \\obtained \: by \: Rabin \: = 56.25

Step-by-step explanation:

 Total\: marks = 80

Rohit \:mark's = 45

 Percentage \: of \: marks \\=\big(\frac{marks\: obtained}{Total \: marks }\big) \times 100

=\frac{45}{80}\times 100

= $\frac{45}{4}\times 5$

=$\frac{225}{4}$

=$56.25$

Therefore,

 Percentage \: of \: marks \\obtained \: by \: Rabin \: = 56.25

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